MOSFET Calculator
MOSFET instantly calculates results using i cut off, i saturation, i triode. Use the calculator above for instant answers in your browser.
The MOSFET Calculator is an essential diagnostic and design tool for electronics engineers, physics students, and hardware hobbyists. By processing key parameters such as gate-source voltage, threshold voltage, and device geometry, this calculator instantly determines current output across cut-off, triode, and saturation operating regimes. It eliminates manual arithmetic errors and accelerates the prototyping of modern semiconductor circuits.
How MOSFET Calculations Work
Metal-Oxide-Semiconductor Field-Effect Transistors operate across distinct physical regions determined by terminal voltages. In the Cut-Off Region, the gate-source voltage ($V_{GS}$) remains below the threshold voltage ($V_{th}$), resulting in zero drain current. In the Triode (Linear) Region, where $V_{DS} < V_{GS} - V_{th}$, the transistor acts like a voltage-controlled resistor using the equation: $I_{triode} = 2 \cdot K_{Mos} \cdot V_{DS} \cdot (V_{GS} - V_{th} - 0.5 \cdot V_{DS})$. In the Saturation Region, where $V_{DS} \ge V_{GS} - V_{th}$, the channel pinches off, and the drain current becomes independent of drain-source voltage, modeled by: $I_{saturation} = K_{Mos} \cdot (V_{GS} - V_{th})^2$. The process constant $K_{Mos}$ integrates physical properties including electron mobility, oxide capacitance, and the channel's width-to-length ratio.
Worked Calculation Example
Consider a MOSFET circuit where the process transconductance parameter $K_{Mos}$ is $0.5 \text{ mA/V}^2$, the gate-source voltage ($V_{GS}$) is $5\text{ V}$, the threshold voltage ($V_{th}$) is $1.5\text{ V}$, and the drain-source voltage ($V_{DS}$) is $3\text{ V}$. First, verify the operating region by checking the condition: $V_{DS}$ ($3\text{ V}$) is greater than $V_{GS} - V_{th}$ ($5 - 1.5 = 3.5\text{ V}$)? Since $3 < 3.5$, the device operates in the triode region. Applying the triode equation: $I_{triode} = 2 \cdot 0.5 \cdot 3 \cdot (5 - 1.5 - 0.5 \cdot 3) = 3 \cdot (3.5 - 1.5) = 3 \cdot 2 = 6\text{ mA}$. Thus, the resulting drain current is $6\text{ mA}$.
Practical Tips for MOSFET Analysis
Always verify your threshold voltage ($V_{th}$) specifications against manufacturer datasheets, as temperature variations can significantly shift this value. Double-check your unit conversions—especially when switching between micrometers for channel dimensions and milliamperes for currents—to prevent massive scale errors. Finally, always evaluate your $V_{DS}$ versus $V_{GS} - V_{th}$ boundaries first before applying triode or saturation formulas to avoid calculating using the wrong physical model.
FAQs
What are the MOSFET operating regimes?
A MOSFET operates primarily in three distinct regions based on terminal voltages. In cut-off, the transistor is turned off with negligible current flow. In the triode or linear region, the channel acts as a variable resistor controlled by the gate voltage. In saturation, the conductive channel pinches off near the drain, causing the drain current to stabilize and remain relatively constant despite increases in drain-source voltage.
Why does the current of a MOSFET saturate?
Current saturation occurs because of channel pinch-off. As the drain-source voltage increases, the voltage drop across the oxide near the drain end decreases, eventually neutralizing the inversion layer and narrowing the conductive channel to a vanishingly small width. Once this pinch-off point is reached, any further increases in drain-source voltage drop entirely across the depleted region, leaving the drift velocity and current through the pinch-off point saturated.
What is the saturation current of a BSS138 MOSFET when the gate tension is 10 V?
To find the saturation current for a specific transistor like the BSS138, input its unique transconductance coefficient and threshold voltage into the saturation formula. Assuming a typical threshold voltage of around 1.5 V and a device parameter yielding a calculated $K_{Mos}$, substitute $V_{GS} = 10\text{ V}$ into $I_{sat} = K_{Mos}(V_{GS} - V_{th})^2$. Always consult the specific manufacturer data curve for exact experimental parameters.
What is the current of a MOSFET in the triode region?
In the triode region, the MOSFET behaves like a linear resistor controlled by the gate voltage. The current depends on both the drain-source voltage and the effective voltage headroom above the threshold. As $V_{DS}$ increases linearly, the current increases proportionally at first, but bends downward as it approaches the saturation boundary due to the reduction of charge density near the drain terminal.
Formula verified against NIST Reference Data — all calculations use deterministic, standards-based formulas.
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