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LC Filter Calculator

Kaushik RabadiyaCreated by Kaushik RabadiyaLast updated: September 24, 2026

LC filter instantly calculates results using c lc, fc lc, l lc. Use the calculator above for instant answers in your browser.

Welcome to the ultimate LC Filter Calculator, designed to help audio engineers, radio frequency specialists, and electronics hobbyists determine critical circuit parameters. Whether you are tuning a power supply filter or designing a passive crossover, this tool instantly computes the resonant cutoff frequency, inductance, or capacitance required for your project. By solving the fundamental reactive relationship between inductors and capacitors, you can eliminate signal noise and ensure optimal frequency response.

How the LC Filter Calculation Works

An LC filter relies on the reactive properties of an inductor (L) and a capacitor (C) to block or pass specific frequency bands. At the core of this passive filter is the resonant or cutoff frequency equation: Fc = 1 / (2 * pi * sqrt(L * C)). In this formula, Fc represents the cutoff frequency in Hertz, L denotes inductance in Henries, and C represents capacitance in Farads. By rearranging this standard mathematical expression, our calculator allows you to solve for any unknown variable—whether you are looking for the exact frequency cutoff of existing components or determining what size capacitor or inductor you need to buy.

Worked Example: Designing a 1 kHz Low Pass Filter

Let us walk through a practical engineering scenario: suppose you need to design an LC low-pass filter with a target cutoff frequency (Fc) of 1,000 Hz, and you have a readily available inductor (L) with a value of 10 millihenries (0.01 H). To find the required capacitance (C), we rearrange the formula to solve for C: C = 1 / ( (2 * pi * Fc)^2 * L ). First, calculate the angular frequency term: 2 * pi * 1000 = 6,283.18. Next, square this value to get 39,478,417. Multiply that result by the inductance (0.01), yielding 394,784.17. Finally, divide 1 by this product: C = 1 / 394,784.17, which results in approximately 2.53 microfarads (uF). Thus, pairing a 10 mH inductor with a 2.53 uF capacitor yields your desired 1 kHz cutoff.

Practical Tips for LC Filter Design

When implementing physical LC filters, always account for component tolerances; standard off-the-shelf capacitors and inductors often deviate by 5% to 20% from their stated nominal values. Additionally, pay close attention to the parasitic resistance (ESR) of your inductors, as high resistance can damp the filter response and reduce overall efficiency. Finally, ensure your chosen components are rated to handle the maximum voltage and current passing through the circuit to prevent saturation or dielectric breakdown.

FAQs

How do you calculate the cutoff frequency of an LC filter circuit?

To calculate the cutoff frequency, take the product of your inductance and capacitance, multiply it by four times the square of pi, and then take the reciprocal of the square root of that product. Expressed mathematically, Fc = 1 / (2 * pi * sqrt(L * C)). This gives you the exact point where the signal attenuation reaches minus three decibels.

What inductor do I need for a 1 kHz LC low pass filter?

The required inductance depends on the capacitance value you choose to pair it with. If you select a standard 1 microfarad capacitor, you would rearrange the formula to solve for L, resulting in an inductance of approximately 25.3 millihenries to achieve a sharp 1 kHz cutoff frequency.

Why is component quality important in passive LC filters?

Component quality directly impacts filter performance because real-world inductors and capacitors contain parasitic elements like equivalent series resistance and stray capacitance. High-quality components with low parasitic losses ensure sharper roll-off slopes, minimal signal distortion, and greater thermal stability under heavy load conditions.

Formula verified against NIST Reference Data — all calculations use deterministic, standards-based formulas.

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